Hello science lovers!
In this article you will get the answers of the following questions:
So, let’s start!
Electric intensity due to a point charge:
[What is point charge?]If the charge body is very small like a point then the charge of the body is called point charge.
Let a positive charge +q situated at a point A in a medium whose dielectric constant is K. Now, we will determine the electric intensity at a point p at a distance r from this charge
Suppose a small charge +q0 is placed at point p.
Now, force acting charge q0 is
F=(1/4πε0k) (q q0 /r2) -(i)
Hence, electric intensity at point p is
E=F/q0
Substituting F from equation (i) we get
E=(1/4πε0k) (q q0/r2q0)
=> E=(1/4πε0k) (q/r2)
=> E=(1/4πε0k) (q/r2) -(ii)
Now for air or vacuum k=1 so equation becomes
E=(1/4πε0) (q/r2)
Learn more about the electricfield intensity due to point charges.
Electric dipole:
[2.What is electric dipole?] A pair of equal and opposite point charge separated by very small distance is called an electric dipole
Here two equal and opposite charge -q and +q are placed 2a distance appoint running as electric dipole.
Electric dipole moment:
[3.What is electric dipole moment] The product of any of the charge of a dipole and the distance the charge is called the electric dipole moment. Its unit is coulomb’s meter. If q is a charge of the dipole and 2a is the distance then the magnitude of the dipole moment is p=qX2a.
In this article you will get the answers of the following questions:
- Expression for electric field intensity due to point charge.
- What is electric dipole?
- What is electric dipole moment?
So, let’s start!
Electric intensity due to a point charge:
[What is point charge?]If the charge body is very small like a point then the charge of the body is called point charge.
Let a positive charge +q situated at a point A in a medium whose dielectric constant is K. Now, we will determine the electric intensity at a point p at a distance r from this charge
Suppose a small charge +q0 is placed at point p.
Now, force acting charge q0 is
F=(1/4πε0k) (q q0 /r2) -(i)
Hence, electric intensity at point p is
E=F/q0
Substituting F from equation (i) we get
E=(1/4πε0k) (q q0/r2q0)
=> E=(1/4πε0k) (q/r2)
=> E=(1/4πε0k) (q/r2) -(ii)
Now for air or vacuum k=1 so equation becomes
E=(1/4πε0) (q/r2)
Learn more about the electricfield intensity due to point charges.
Electric dipole:
[2.What is electric dipole?] A pair of equal and opposite point charge separated by very small distance is called an electric dipole
Here two equal and opposite charge -q and +q are placed 2a distance appoint running as electric dipole.
Electric dipole moment:
[3.What is electric dipole moment] The product of any of the charge of a dipole and the distance the charge is called the electric dipole moment. Its unit is coulomb’s meter. If q is a charge of the dipole and 2a is the distance then the magnitude of the dipole moment is p=qX2a.
Thanks a lot bro
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Deletethanks too!!
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